Eddie Woo
Eddie Woo
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Відео

Statistical Proportions (2 of 2: Basic example)
Переглядів 3 тис.9 годин тому
More resources available at www.misterwootube.com
Statistical Proportions (1 of 2: What are they?)
Переглядів 4,7 тис.16 годин тому
More resources available at www.misterwootube.com
Independent Events (2 of 2: Overlapping situations)
Переглядів 3,4 тис.День тому
More resources available at www.misterwootube.com
Independent Events (1 of 2: Thinking symbolically)
Переглядів 4,4 тис.14 днів тому
More resources available at www.misterwootube.com
Conditional Probability (4 of 4: Determining reduced sample space)
Переглядів 4,8 тис.14 днів тому
More resources available at www.misterwootube.com
Conditional Probability (3 of 4: Defective light bulbs)
Переглядів 5 тис.21 день тому
More resources available at www.misterwootube.com
Conditional Probability (2 of 4: Introductory example)
Переглядів 8 тис.21 день тому
More resources available at www.misterwootube.com
Conditional Probability (1 of 4: Establishing foundations)
Переглядів 10 тис.28 днів тому
More resources available at www.misterwootube.com
TeachCast with Eddie Woo (excerpt)
Переглядів 10 тис.3 місяці тому
Full interview available on the second channel: ua-cam.com/video/Lcs0t6cihI0/v-deo.html To view more episodes of TeachCast, visit: ua-cam.com/play/PLT6d9SvBTGMG4U9qBI5pNzuFe-qJhF-Ut.html Thanks to @teachnsw for producing and sharing this video! More resources available at www.misterwootube.com
Happy Pi Day!
Переглядів 32 тис.3 місяці тому
More resources available at www.misterwootube.com
Ask Me Anything!
Переглядів 13 тис.4 місяці тому
Head over to the @sydney_uni channel to watch the other half of this video: ua-cam.com/video/OsjXU9Ju_J0/v-deo.html More resources available at www.misterwootube.com
🇺🇸 I'm visiting the United States!
Переглядів 12 тис.4 місяці тому
This has been a long time coming! US friends - if you have contacts or colleagues who might be interested in having me speak or run workshops, please reach out. More details available if you DM or email (info@misterwootube.com)!
What if I feel like mathematics isn’t for me? Eddie Woo on the Solutionists
Переглядів 15 тис.5 місяців тому
Listen to the full podcast episode: protect-au.mimecast.com/s/dmDGC91WPRTzLLAMPuoMtpF?domain=pod.fo More resources available at www.misterwootube.com
Is growth mindset actually real? Eddie Woo on the Solutionists
Переглядів 10 тис.5 місяців тому
Listen to the full podcast episode: protect-au.mimecast.com/s/dmDGC91WPRTzLLAMPuoMtpF?domain=pod.fo More resources available at www.misterwootube.com
Is lifelong learning really possible? Eddie Woo on the Solutionists
Переглядів 8 тис.6 місяців тому
Is lifelong learning really possible? Eddie Woo on the Solutionists
Eddie Woo's Wonderful World of STEM | Studio 10
Переглядів 12 тис.7 місяців тому
Eddie Woo's Wonderful World of STEM | Studio 10
Jack the Hunter (2 of 2: Explaining the trick)
Переглядів 12 тис.7 місяців тому
Jack the Hunter (2 of 2: Explaining the trick)
Jack the Hunter (1 of 2: Performing the trick)
Переглядів 17 тис.8 місяців тому
Jack the Hunter (1 of 2: Performing the trick)
Question 30 (this year's HSC Mathematics Advanced exam)
Переглядів 145 тис.8 місяців тому
Question 30 (this year's HSC Mathematics Advanced exam)
Worked Probability Questions (3 of 3: Disease testing)
Переглядів 16 тис.9 місяців тому
Worked Probability Questions (3 of 3: Disease testing)
Worked Probability Questions (2 of 3: Selecting sock pairs)
Переглядів 10 тис.9 місяців тому
Worked Probability Questions (2 of 3: Selecting sock pairs)
Worked Probability Questions (1 of 3: Venn diagram)
Переглядів 12 тис.9 місяців тому
Worked Probability Questions (1 of 3: Venn diagram)
Circumcentre of a Triangle (2 of 2: Proving orthogonality)
Переглядів 8 тис.9 місяців тому
Circumcentre of a Triangle (2 of 2: Proving orthogonality)
Circumcentre of a Triangle (1 of 2: Finding the bisector vector)
Переглядів 8 тис.9 місяців тому
Circumcentre of a Triangle (1 of 2: Finding the bisector vector)
Vector Geometry Proofs (3 of 3: Using deductive vector logic)
Переглядів 7 тис.10 місяців тому
Vector Geometry Proofs (3 of 3: Using deductive vector logic)
Vector Geometry Proofs (2 of 3: Angle in a semicircle)
Переглядів 8 тис.10 місяців тому
Vector Geometry Proofs (2 of 3: Angle in a semicircle)
Vector Geometry Proofs (1 of 3: An unexpected quadrilateral property)
Переглядів 9 тис.10 місяців тому
Vector Geometry Proofs (1 of 3: An unexpected quadrilateral property)
9 News segment: Preparing for HSC exams
Переглядів 13 тис.10 місяців тому
9 News segment: Preparing for HSC exams
Cartesian & Vector Equations (3 of 3: Solving vector equations)
Переглядів 4,8 тис.10 місяців тому
Cartesian & Vector Equations (3 of 3: Solving vector equations)

КОМЕНТАРІ

  • @KOTRT777
    @KOTRT777 22 хвилини тому

    9

  • @sobreaver
    @sobreaver 24 хвилини тому

    I'm half way through and have no freaking clue why I keep watching if not by mere curiosity and great enthusiastic explanation. The abstraction have always been annoying to me but the mathematical prowess have still always been interesting, to lock things in a logical place of understanding and a mechanical processing that guides me between the unknown real shape of reality and my swimming through with my imagination gap filling 'power'.

  • @elonmusk78605
    @elonmusk78605 Годину тому

    Ans should be only 9

  • @SumanChakra-td3wu
    @SumanChakra-td3wu Годину тому

    But shan't we obey BODMAS rule

  • @SumanChakra-td3wu
    @SumanChakra-td3wu Годину тому

    Sir your videos are amazing but please work to reduce reverberations in your classroom

  • @platogenova9573
    @platogenova9573 2 години тому

    The Boss, Mr Hoskin, would not approve. Where are the Australians?

  • @damxon
    @damxon 2 години тому

    The answer is not 9 because what is we replace ÷ by /

  • @yor_201
    @yor_201 2 години тому

    Well, according to the rule there should only be one answer. That is 9. The rule is bodmas. First, you solve what's inside the Brackets, then "off" which is simply multiplication but with different sign. There's no "Off" in it, so next is Divide. Hence, we first do the brackets which equates to 3, then "off" but its absent, so we do division of 6 by 3 which equates to 3, then multiplication which equates to 9, the only answer according to me. Butttt...don't believe me. That guy's a profesional mathematician with far more experiece than me. If he's saying it can be both then it can be both. There must be something wrong with the explanation I gave.

  • @useoiut
    @useoiut 2 години тому

    its 7

    • @useoiut
      @useoiut 2 години тому

      6:2(1+2)=1 you always start with (x)

  • @ArifBillahOnGoogle
    @ArifBillahOnGoogle 3 години тому

    Since I'm not anything close to being a math guy, the only thing that I understand from this video is that it's a math class! Fantastic!

  • @14.arjunS
    @14.arjunS 3 години тому

    Obvious answer is mitochondria

  • @ArifBillahOnGoogle
    @ArifBillahOnGoogle 4 години тому

    9

  • @throplagm
    @throplagm 4 години тому

    It's Yes, 1

  • @ernoa1775
    @ernoa1775 5 годин тому

    It's 9

  • @happygood18
    @happygood18 5 годин тому

    To determine the value of the expression 6÷2(1+2), we need to follow the order of operations, often abbreviated as *PEMDAS/BODMAS:* P/B: Parentheses/Brackets E/O: Exponents/Orders (i.e., powers and square roots, etc.) MD: Multiplication and Division (from left to right) AS: Addition and Subtraction (from left to right) Let's break down the expression step by step: 1. Parentheses/Brackets: Evaluate inside the parentheses first. 1+2=3 So the expression becomes: 6÷2(3) 2. Multiplication and Division (from left to right): Perform the division and multiplication from left to right. Here we have two operations: division and multiplication. According to the order of operations, we proceed from left to right. 6÷2×3 First, perform the division: 6÷2=3 Then, multiply the result by 3: 3×3=9 Therefore, the expression evaluates to 9. *Explanation:* The confusion often arises because some might interpret the expression differently, grouping 2(3) together before performing the division. However, according to standard mathematical conventions (PEMDAS/BODMAS), multiplication and division are performed from left to right as they appear. Thus, the correct and mathematically logical interpretation of the expression 6÷2(1+2) is: 6÷2×3=3×3=9 *So, the answer is 9.*

  • @Pitoe.
    @Pitoe. 7 годин тому

    This guy is wrong. The division symbol only holds true for the term after it (which is 2 in this case). If you wanted to include the (1+2) within that division process, you would have to write the equation like this : 6÷(2(1+2)). Then the answer would be 1. Another problem people I saw is that people don't know that if there is brackets without any symbol it implies you have to multiply. So 2(1+2) = 2 x (1+2). Follow these rules and you will see the correct answer is 9.

  • @AMITSAHNI803
    @AMITSAHNI803 7 годин тому

    1

  • @More.A-gf5rd
    @More.A-gf5rd 7 годин тому

    It's 9.

  • @AlameenAdeyemi
    @AlameenAdeyemi 10 годин тому

    I actually had fun watching this

  • @Justinnn_yq
    @Justinnn_yq 11 годин тому

    but how do you go from 0! to -1! with the same logic of from a^0 to a^-1? what do you divide it by?

  • @Hobopower84
    @Hobopower84 12 годин тому

    Why isn't the binomial variance n*p*q?

    • @nurgul_m
      @nurgul_m 46 хвилин тому

      Because of Law of Large Numbers

  • @RA-il3rw
    @RA-il3rw 12 годин тому

    Wish I saw this before my maths exam 😭

  • @NYaw-mm3jc
    @NYaw-mm3jc 12 годин тому

    I wish you had a full lesson on binomial theorem

  • @fas9320
    @fas9320 12 годин тому

    I feel a desperate need to learn English because of your videos because I use the translator and I feel excluded. 🙂😭

  • @smial-_-4773
    @smial-_-4773 13 годин тому

    Great to see CTHS is working on their assessments lol

  • @HappyKaci
    @HappyKaci 13 годин тому

    Good luck from NYC! ❤ Have a great trip, it would be great to go to your lectures at NY. Wish you a well planned smooth journey in US 🎉

  • @prudvitejach5875
    @prudvitejach5875 14 годин тому

    1st comment

  • @rozbiynik3986
    @rozbiynik3986 16 годин тому

    1)6÷2(1+2) 2)6÷2×3 3)3×3=9

  • @jxderin
    @jxderin 16 годин тому

    7:45 timestamp

  • @gmrachit7964
    @gmrachit7964 19 годин тому

    9

  • @rbjassoc6
    @rbjassoc6 20 годин тому

    That was fun :-)

  • @amrithmadhu1523
    @amrithmadhu1523 21 годину тому

    What I personally think the reason for the principal argument to be restricted between -pi and pi is because of the ease of multiplication. When we multiply two or more complex numbers they elongate by the combined (product) modulus and rotate by the combined (sum) argument . The disjoint interval given for the principal argument helps if multiplication was considered as a transformation such that the product measures as 1+ 0i in the transformed coordinate system. When there are multiple complex numbers in the same argand plane this basis transformation could be helpfull. Some problems in physics are solved in such a way. Hope this helps.

  • @tanyasharma8465
    @tanyasharma8465 21 годину тому

    Nice video ❤

  • @user-oj3ky2ee9q
    @user-oj3ky2ee9q 21 годину тому

    #dayan kiriwaththuduva a mathematician says 1 divided by zero is postive or negative infinity so please come to an conclusion

  • @salman-hm8zf
    @salman-hm8zf 22 години тому

    the correct answer is 9. multiplication and division are at the same level , so you do them left to right . the problem becomes 3*3=9

  • @CalculusIsFun1
    @CalculusIsFun1 23 години тому

    Ambiguity is the worst. Use brackets to negate it to the best of your ability, because math isn’t supposed to be about finding different ways to interpret the same thing it’s about problem solving. This is stupid. We shouldn’t force ambiguity like this and should just use better notation. Brackets, use the / instead of divide by symbol, etc.

  • @vladof_putler
    @vladof_putler 23 години тому

    6÷2(2+1) = 6 ÷ 4 +2 = 3.5 💀💀💀💀 Lol just kidding

  • @vedaswaroopkarri9418
    @vedaswaroopkarri9418 День тому

    I did this with calculator and GOT 9 NOT 1

  • @Omkar_Rangole
    @Omkar_Rangole День тому

    The answer is 9 obviously In mathematics we dont use ÷ symbol for the same reason The equation is (6/2)(1+2) And not 6/[2(1+2)] Thats why it is 9 And not 1 The (1+2) part is in numerator and not denominator

  • @h0oa
    @h0oa День тому

    i thought it was 6

    • @GanonTEK
      @GanonTEK День тому

      Do you treat juxtaposition with brackets as implied addition?

    • @h0oa
      @h0oa День тому

      @@GanonTEK I’m just stupid

    • @GanonTEK
      @GanonTEK День тому

      @@h0oa I've seen othere say 6 so I was wondering if it was specific to some countries maybe. Like how some say 0 is the answer as in some countries ÷ means subtract so 0 is correct there.

    • @h0oa
      @h0oa День тому

      @@GanonTEK here is how i did it : (1+2) = 3 6/2 = 3 3+3 = 6 and the answer is wrong because it's been time for me doing math after graduating from high school.

  • @rameshjain4703
    @rameshjain4703 День тому

    great sirvm i am Ramesh from india, kindly make it with some activity

  • @nziji
    @nziji День тому

    UGHH, why study in my class not as happy as here

  • @bhatuzair1212
    @bhatuzair1212 День тому

    It's 7

    • @GanonTEK
      @GanonTEK День тому

      7 is wrong for the same reason 4(1+1)/2 = (4+4)/2 = 8/2 = 4 and not 4+4/2 = 4+2 = 6. Distribution brings terms into brackets, not out. A common misconception. Also, if what you are distributing is in the numerator (or denominator) before Distribution, then the result must still remain in the numerator (or denominator) after distribution or you're changing the question.

    • @bhatuzair1212
      @bhatuzair1212 День тому

      Then is it 1 or not ​@@GanonTEK

    • @GanonTEK
      @GanonTEK День тому

      @@bhatuzair1212 1 is a valid answer. If you interpret multiplication by juxtaposition as implying grouping then 6÷2(1+2) means 6÷(2×(1+2)) which is 6÷(2+4) = 6÷6 = 1 If you interpret juxtaposition literally you instead get 6÷2×(1+2) which is (6÷2 + 6) = 3 + 6 = 9. It all comes down to which interpretation of multiplication by juxtaposition you use. It's seen as bad notation here. (6/2)(1+2) and 6/(2(1+2)) are both clear instead.

    • @bhatuzair1212
      @bhatuzair1212 21 годину тому

      @@GanonTEK than you

  • @SyedShuvo707
    @SyedShuvo707 День тому

    9

  • @mr_intersteller
    @mr_intersteller День тому

    Why did i came here ? Asn: just for entertainment😂

  • @1mixtercook
    @1mixtercook День тому

    If you use BEDMAS then its 9

    • @GanonTEK
      @GanonTEK День тому

      You get both 1 and 9 with BEDMAS. It depends on the interpretation of multiplication by juxtaposition used that determines 1 or 9.

  • @JoseMiguelMendozaLippay-s8t
    @JoseMiguelMendozaLippay-s8t День тому

    There’s no way this equation could be 1 but 9, is just wrong to multiple 2 times 1+2 since you literally have a division right next the 2. You could either resolve the division first which will get you 3 and then multiply by (1+2) or solve 1+2 times 6/2. I don’t even think mathematically speaking that the answer 1 is correct in terms of order and rules.

    • @GanonTEK
      @GanonTEK День тому

      Academically, multiplication by juxtaposition implies grouping so that makes 1 just as valid.

  • @GF86123
    @GF86123 День тому

    2:15 he is a magician as well 😂😂😂

  • @ukaszkiepas57
    @ukaszkiepas57 День тому

    WOW. Respect

  • @ukaszkiepas57
    @ukaszkiepas57 День тому

    awesome!